Odisha · Vidhan Sabha (State Assembly) Election 2019
Shankar Oram of Bharatiya Janta Party won the Biramitrapur Vidhan Sabha (Assembly) constituency in Odisha in the 2019 state assembly election, securing 60,937 votes (35.00% vote share). The runner-up was Makhlu Ekka (Biju Janata Dal) with 44,586 votes.
A total of 8 candidates contested this assembly seat. State Assembly elections elect Members of the Legislative Assembly (MLAs) using India's First-Past-The-Post (FPTP) system, and the party or alliance winning a majority of seats forms the state government. Full candidate-wise vote breakdown, vote shares, and constituency information are shown below.
| Position | Candidate Name | Votes | Votes% | Party |
|---|---|---|---|---|
| 1 | Shankar Oram | 60937 | 35.00% | Bharatiya Janta Party |
| 2 | Makhlu Ekka | 44586 | 25.60% | Biju Janata Dal |
| 3 | Rohit Joseph Tirkey | 44212 | 25.40% | Indian National Congress |
| 4 | Sebeyan Aind | 14374 | 8.30% | Jharkhand Mukti Morcha |
| 5 | Peter Topno | 4455 | 2.60% | Independent |
| 6 | Paulus Oram | 2532 | 1.50% | Bahujan Samaj Party |
| 7 | Binay Kullu | 1835 | 1.10% | Aam Aadmi Party |
| 8 | Mansid Ekka | 1088 | 0.60% | Independent |
The Biramitrapur constituency is part of the Odisha Vidhan Sabha (Legislative Assembly). In the 2019 Assembly election, 8 candidates contested for this seat. Shankar Oram (Bharatiya Janta Party) emerged as the winner securing 60,937 votes.
State Assembly elections in India determine which party or coalition forms the state government. The party or alliance winning a majority of Assembly seats in a state gets to form the government and appoint the Chief Minister. Unlike Lok Sabha elections which are held simultaneously across India, each state follows its own election cycle, typically every five years.
How to read this data: The candidate table above shows all contestants ranked by position. The vote percentage column shows each candidate's share of the total votes polled in this constituency. The bar chart visualizes the top candidates' vote counts for quick comparison.